[EM] Fwd: Schrodinger's Candidate
Forest Simmons
forest.simmons21 at gmail.com
Thu Oct 14 19:16:50 PDT 2021
Second try ...
---------- Forwarded message ---------
From: Forest Simmons <forest.simmons21 at gmail.com>
Date: jue., 14 de oct. de 2021 6:55 p. m.
Subject: Schrodinger's Candidate
To: EM <Election-methods at lists.electorama.com>
Just as Schrodinger's Cat remains in a superposition of two states (alive
and dead) until the decisive resolution of its wave function into a
definite eigenstate occasioned by an observational "measurement"
disturbance (opening and inspecting the contents of the box), so also
Schrodinger's Candidate remains in a superposition of Good/Bad,
Winner/Loser, until the ballots are voted and tallied.
In this method each voter chooses for each candidate a mark from the range
...
Ultra Hyper Bad, Very Bad, Pretty Bad, Pretty Good, Very Good, and Super
Dooper Good or UHB, VB, PB, PG, VG, and SDG, respectively... six judgments
... three each of negative and positive connotations that an English major
could profitably standardize for our patriotic cause.
We cannot avoid numbers forever ... at very least we need to tally the
ballots for and against each candidate X..... accordingly for each of the
three gradations gamma of goodness let B(X, gamma) be the number of ballots
on which candidate X is graded Better than or equal to gamma ... and for
each of the three gradations beta of badness, let W(X, beta) be the number
of ballots on which X is graded Worse than or equal to beta.
For each candidate X we form two polynomials in epsilon... one where the
coefficients are the B for Better values, and another where the
coefficients are the W for Worse values:
P+ = Sum (k = 0, 1, 2) of
Gamma(k)*epsilon^k,
and
P- = Sum (k in 0, 1, 2) of
Beta(k)*epsilon^k
Gamma(0, 1, 2 ) = PG, VG, SDG
Beta(0, 1 ,2) = PB, VB, UHB
For each X determine if P+ or P- is greater for positive infinitesimal
epsilon.
This reveals which candidates are Good and which are Bad after the "wave
collapse"....
To Be Continued ....
Let P(X) = P
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