[EM] [CES #15276] Re: PAR: nearly-equivalent rules

[C.Benham]

The proposed method has an easy Push-over incentive and fails FBC and 
Condorcet.

Chris Benham


On 11/15/2016 10:43 AM, Jameson Quinn wrote:
> Nevin's proposed method is pretty good, but it suffers from a slippery 
> slope problem in a chicken dilemma scenario.
>
> 2016-11-14 17:54 GMT-05:00 Nevin Brackett-Rozinsky 
> <nevin.brackettrozinsky at gmail.com 
> <mailto:nevin.brackettrozinsky at gmail.com>>:
>
>     How about something like this:
>
>     1. Voters indicate whether they Prefer, Accept, or Reject each
>     candidate.
>     2. Identify the candidate with the most Prefer votes, call them P.
>     3. Identify the candidate with the most Accept-or-better votes,
>     call them Q.
>     4. Elect the head-to-head winner between P and Q.
>
>     For step 4, this means to count the number of ballots which rate P
>     ahead of Q, and vice versa, and elect whichever is higher up on
>     more ballots.
>
>     Essentially, this method looks at the ballots and says, “We know
>     who the most voters prefer, and we know who the most voters
>     accept, but which of them should win? Hey, I know, we can let the
>     votes decide!”
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