[EM] C//A
C.Benham
cbenhamau at yahoo.com.au
Thu Jun 16 08:50:24 PDT 2011
Forest Simmons wrote (12 June 2011):
> I think the following complete description is simpler than anything
> possible for ranked pairs:
>
> 1. Next to each candidate name are the bubbles (4) (2) (1). The
> voter rates a candidate on a scale from
> zero to seven by darkening the bubbles of the digits that add up to
> the desired rating.
>
> 2. We say that candidate Y beats candidate Z pairwise iff Y is rated
> above Z on more ballots than not.
>
> 3. We say that candidate Y covers candidate X iff Y pairwise beats
> every candidate that X pairwise
> beats or ties.
>
> [Note that this definition implies that if Y covers X, then Y beats X
> pairwise, since X ties X pairwise.]
>
> Motivational comment: If a method winner X is covered, then the
> supporters of the candidate Y that
> covers X have a strong argument that Y should have won instead.
>
> Now that we have the basic concepts that we need, and assuming that
> the ballots have been marked
> and collected, here's the method of picking the winner:
>
> 4. Initialize the variable X with (the name of) the candidate that
> has a positive rating on the greatest
> number of ballots. Consider X to be the current champion.
>
> 5. While X is covered, of all the candidates that cover X, choose the
> one that has the greatest number of
> positive ratings to become the new champion X.
>
> 6. Elect the final champion X.
>
> 7. If in step 4 or 5 two candidates are tied for the number of
> positive ratings, give preference (among the
> tied) to the one that has the greatest number of ratings above level
> one. If still tied, give preference
> (among the tied) to the one with the greatest number of ratings above
> the level two. Etc.
>
> Can anybody do a simpler description of any other Clone Independent
> Condorcet method?
Forest,
I like this Condorcet method very much and endorse it.
The 8-slot (including zero) addition ratings ballot idea is clever, but
would it really be acceptable as a public proposal in the US?
Chris Benham
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