[EM] Joe: Could you explain the question?
Michael Ossipoff
mikeo2106 at msn.com
Tue Jan 23 05:37:59 PST 2007
Joe--
You asked what is the role of 1/e in the formula for Bias-Free's round-off
point. I tried to answer by saying that ((b^b)/(a^a))(1/e) is just the
result I got when looking for the round-off point that would make cycles'
s/q = 1. That's all I can say about where the formula came from.
What was the meanng of your question? In what sense was "role" intended?
Unless I made an error (and I probably didn't make an error), the formula
for Weighted Bias-Free doesn't contain "e". Weighted Bias-Free is gotten by
a/q-1 and b/q-1 by a weight that approximates the frequency density of
states at a particular q value. I approximate that density function by:
B/(q+A), which has the same general behavior as the distribution function,
though of course it will be a rough approximation.
Mike Ossipoff
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