[EM] simple question (I think)
kislanko at airmail.net
Wed Nov 16 16:15:05 PST 2005
"Candidates A, B and C all have 8 pairwise wins. D has 7. Could D still be
chosen as the winner by any "reasonable" method? "
Sure. D's 7 pairwise wins could be by a large enough majority that the
"extra" pairwise win that A, B, and C have over the fringe candidate that
beats D by 1 vote makes the "8" vs "7" irrelevant.
This is kind of why I don't like any counting method that BEGINS with the
pairwise matrix. Some systems would eliminated D when all of A, B, and C are
real dogs that no majority likes.
Rob brown :
Hi, I haven't been around for a good while but some of you may remember me.
I have recently been playing around with some stuff for scoring condorcet
elections, and ran into a question that seemed obvious but maybe not:
Is it possible, in any of the Condorcet election methods (beatpath, ranked
pairs, etc), for someone who has fewer pairwise wins than another candidate,
to win the election regardless?
For instance, say there is no Condorcet winner. Candidates A, B and C all
have 8 pairwise wins. D has 7. Could D still be chosen as the winner by
any "reasonable" method?
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