[EM] IRV _does_ meet IICC

[MIKE OSSIPOFF]

In a rather careless error, I said yesterday that IRV fails IICC, the weaker 
relative of ICC that involves an indifferent set instead of a clone set. 
Actually IRV passes that, just as it passes ICC. IICC is easier to pass, and 
I don't know of anything that passes ICC without passing IICC. I haven't 
really looked for such a method, but it's likely there isn't one, since 
every indifferent set is a clone set.

Mike Ossipoff

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