[EM] Intuitive argument that FPTP manipulability approaches certainty in impartial culture
Kristofer Munsterhjelm
km-elmet at munsterhjelm.no
Thu Apr 17 13:43:25 PDT 2025
Suppose, for any given election, we relabel candidates so that they are
in sorted order by first preferences, i.e. A has the most first
preferences, then B, then C, and so on.
A wins in the honest election.
Then the election is manipulable if, when every X>A voter ranks X first,
the winner changes from A to X.
For a three-candidate election, specifically, we can manipulate if
fpA > fpB and (B>A) > fpA,
because then all B>A voters rank B first and fpB becomes equal to B>A
which is greater than fpA.
Now consider the impartial culture with c candidates and n voters. Every
first preference count is a binomial with expectation n/c, while every
pairwise preference has expectation n/2.
Since n/2 > n/c when we have more than two candidates, in the limit of n
approaching infinity, we should have (B>A) > fpA with probability one.
Thus Plurality is almost always manipulable under impartial culture with
enough voters.
(What's needed to make this formal rather than just intuitive is an
argument that uses the variance of the binomials to show that p((B>A) >
fpA) = 1 in the limit of n approaching infinity.)
I suspect that certain manipulability under IC is true of at least every
three-candidate weighted positional system closer to Plurality than
Borda, but proving that would be pretty tough. I did some calculations
that, if I didn't mess them up, shows that it's *not* true for
Antiplurality.
-km
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