[EM] Cloneproof tournaments
Kristofer Munsterhjelm
km_elmet at t-online.de
Fri Mar 24 06:15:26 PDT 2023
I got to thinking about whether it's possible to make a cloneproof
elimination tournament-based voting method, and I thought I should start
at the obvious (way too strong) formulation:
Suppose that we let the seeding order be provided by some function f of
the election. (This is cheating, but I'm trying to see if I can devise a
cloneproof f; if I can't, then it definitely isn't cloneproof under
normal conditions.)
Then intuitively, the following should work: Let f be a seed order so
that the Ranked Pairs winner wins. Then the tournament augmented with f
is cloneproof because Ranked Pairs is, and the RP winner is made to
always win. Of course, this treats the elimination tournament as a mere
afterthought.
But, to make this rigorous, I would have to show that for any Smith set
candidate, it is possible to arrange a seeding order so that that
candidate wins. This seems intuitively correct, but intuition isn't proof.
So suppose that we have a Smith set of size 2^n. Then we have to show
that it's possible to arrange the brackets so that we can make any half
of the set drop out. My idea then would be something in the vein of:
suppose A and B are in the Smith set and we need them to be eliminated.
Then A and B can't be beating everybody else in the Smith set; otherwise
those other candidates wouldn't be in the Smith set. So pair A with some
X who beats A pairwise, and pair B with some Y who beats B pairwise.
But the difficult part is that we can't ensure that X and Y are
different candidates. Put differently, we would need to show that for
any partition of the Smith set into two equal parts, it's possible to
arrange the candidates in the first set so that the kth candidate in the
first set beats the kth in the second. Is that always possible? I'm not
actually sure! This sounds very demanding. So perhaps it isn't that
easy... Suppose we have sets {ABC} and {DEF}, and it's possible, and the
arrangement is "A beats D, B beats E, C beats F". Now consider the sets
{ABF}, {DEC}. How could there still be a viable rearrangement since C
beats F?
Any ideas?
(I'm leaving byes out of it for now.)
-km
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