[EM] “Monotonic” Binomial STV
Richard Lung
voting at ukscientists.com
Sat Feb 26 04:21:03 PST 2022
Thank you, Forest,
Your example is the kind of example that Riker gave.
Here the quota equals 50 = 100/[1+1].
Original profile:
Election Keep value is quota/candidate vote:
for A 50/35
B: 50/33
C: 50/32
Exclusion keep value = quota/candidate reverse vote:
for A: 50/33
B: 50/32
C: 50/35
Final (geometric mean) keep values, divide election keep value by
exclusion keep value.
(This is equivalent to multiplying by the inverse exclusion keep value,
as a make-shift second opinion election keep value.)
for A: 50/35 x 33/50. And take their square root ~ ,971
for B: 50/33 x 32/50. As above, gives ~ .9847
for C: 50/32 x 35/50. ... gives ~ 1.0458
Keep values below unity are technically electable. A wins, with lowest
keep value.
New profile:
Election divided by exclusion keep values:
A: 50/37 x 31/50. Take square root of 31/37, for ~ .9153
B: 50/31 x 32/50. As above, ~ 1.016
C: 50/32 x 37/50. As above, ~ 1,075
Again, A is elected as before, and with a yet lower keep value, as the
extra preferences for A warrant.
Regards,
Richard Lung.
On 26/02/2022 01:30, Forest Simmons wrote:
> Richard,
>
> Here's an example of monotonicity failure in conventional single
> winner STV as I understand it:
>
> Original profile of ballots:
>
> 35 A>B>C
> 33 B>C>A
> 32 C>A>B
>
> C eliminated and A wins.
>
> New profile: two members of B faction defect to A faction:
>
> 37 A>B>C
> 31 B>C>A
> 32 C>A>B
> Now B is eliminated and C wins.
>
> How does Binomial STV avoid this monotonicity failure?
>
> Thanks!
>
> -Forest
>
> El jue., 24 de feb. de 2022 10:36 a. m., Richard Lung
> <voting at ukscientists.com> escribió:
>
>
> “Monotonic” Binomial STV
>
> I was told (hello Kristofer) that I could not say that binomial
> STV is “monotonic”unlike traditional or conventional STV. But I
> gave my reasons why I could say this, and they were not
> contradicted or even answered. It is not tabu or forbidden to say,
> and say again, what there is good reason to believe is true,
> whatever the prevailing view.
>
> In conventional STV, the transfer of surpluses, over a quota, to
> next preferences is monotonic. There is “later no harm” unlike the
> Borda count. The intermediate Plant report quoted a non-monotonic
> test example from Riker, to justify their rejection of STV. This
> was based solely on the perverse outcome of a different candidate
> being last past the post, for elimination.
>
> Riker made the unsupported claim that STV is “chaotic.” From a
> century of STV usage, he did not provide a single real case of
> this. The record is that STV counts well approximate STV votes,
> all things considered.
>
> A paper that tried to provide some doubt, of STV as a well-behaved
> system, drew not on a conventional STV election of candidates, but
> on NASA using STV for outer space engineers to vote on a set of
> best trajectories (I forget where).
>
> Traditional STV is not “chaotic”. It is not even wrong. It is just
> an initial or first approximation of binomial STV, a zero order
> binomial STV.
>
> Zero order STV is a uninomial count that does not clearly
> distinguish between an election count or an exclusion count. In
> 1912, HG Wells said of FPTP, we no longer have elections we only
> have Rejections. From first order Binomial STV, the two counts,
> election and exclusion counts, are clearly distinguished and both
> made operational.
>
> Binomial STV does not exclude candidates during the count. It uses
> an exclusion count, to help determine a final election. This
> exclusion count is exactly the same or symmetrical to the
> (monotonic) transfer of surplus votes in an election count.
>
> In both election and exclusion counts, Gregory Method or the
> senatorial rules are expressed in terms of keep values, which
> enable proper book-keeping of all preferences. Keep values can
> keep track of all the preference votes, including abstentions. So,
> no perverse results are possible from the chance exclusion of
> preferences from this or that candidate last past the post. This
> is also why binomial STV is one complete dimension of choice.
>
> Binomial STV has “Independence of Irrelevant Alternatives.” For
> instance, it makes no difference what level the quota is set, to
> the order of the candidates keep values, their order of election.
> It is just that bigger quotas raise the threshold of election.
>
> Regards,
>
> Richard Lung.
>
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>
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