# [EM] So I got an email... / IIA

Forest Simmons forest.simmons21 at gmail.com
Mon Apr 11 17:42:36 PDT 2022

```Kevin's suggestion's simplicity may make it the best choice in this context
...
the method where
each candidate's score is that candidate's first preferences minus the
first preferences of the candidate who beats that candidate and has the
most first preferences.

I suggest the rewording

Elect the the candidate whose top preference count most greatly exceeds
(when greater) or most nearly equals (when smaller) the greatest top
preference count of any candidate defeating it pairwise.

In other words, compare the number fX of first place preferences of
candidate X, and the greatest number fY of first place preferences of any
candidate Y among those defeating X pairwise. Elect the candidate X with
the most favorable comparison between fX and fY.

-Forest

El lun., 11 de abr. de 2022 8:03 a. m., Forest Simmons <
forest.simmons21 at gmail.com> escribió:

>
>
> El lun., 11 de abr. de 2022 6:09 a. m., Kristofer Munsterhjelm <
> km_elmet at t-online.de> escribió:
>
>> On 11.04.2022 10:48, Kristofer Munsterhjelm wrote:
>>
>> > Kevin Venzke's rule that also passes single-candidate DMTBR might be
>> > more well-behaved yet more complex still:
>> >
>> > Elect the CW if there is one, otherwise each candidate's score is the
>> > sum of that candidate's first preferences plus the first preferences of
>> > every candidate he beats. Elect the candidate with the highest score.
>>
>> I mustn't have been properly awake. Kevin suggested the method where
>> each candidate's score is that candidate's first preferences minus the
>> first preferences of the candidate who beats that candidate and has the
>> most first preferences.
>>
>> The sum variant suggestion was mine, and it is:
>>
>> Elect the CW if there is one, otherwise each candidate's score is that
>> candidate's first preferences minus the sum of first preferences of
>> every candidate who beats him. Elect the candidate with the highest score.
>>
>
> I like it!
>
> Possible rewording ...
>
> Lacking a CW, elect the alternative whose top preference count most nearly
> surpasses the top preference total of the alternatives that beat it
> pairwise.
>
>
>
>> -k
>>
>
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