[EM] RCIPE version 2

[Kristofer Munsterhjelm]

Before I respond properly, I'd like to check that I've got your proposed 
"sum of candidates ranked lower" elimination mechanism right.

In this election:

13: D>A>F>B>C>E
11: C>F>A>E>B>D
9: B>C>F>A>E>D
7: A>B>E>D>F>C
7: E>B>F>A>C>D

I calculate the candidate counts as:

A has 152 arrows
B has 138 arrows
C has 111 arrows
D has 79 arrows
E has 87 arrows
F has 138 arrows

so D would be eliminated if there were no Condorcet loser. Is that 
right? (D happens to be the Condorcet loser anyway; I'm just asking 
about your particular fallback mechanism.)

And if that's right, what would A's count be given the ranking

1: A>B>C=D=E=F

is it 5 or 2?

-km