[EM] proportional constraints - help needed

Kristofer Munsterhjelm km_elmet at lavabit.com
Tue Feb 5 11:36:06 PST 2013


On 02/05/2013 06:50 PM, Peter Zbornik wrote:
> The problem (after a slight simplification) is as follows:
> We want to elect five seats with any proportional ranking method (like
> Schulze proportional ranking, or Otten's top-down or similar), using
> the Hagenbach-Bischoff quota
> (http://en.wikipedia.org/wiki/Hagenbach-Bischoff_quota) under the
> following constraints:
> Constraint 1: One of the first two seats has to go to a man and the
> other seat has to go to a woman.
> Constraint 2: One of seat three, four and five has to go to a man and
> one of those seats has to go to a woman.
> Say the "default" proportional ranking method elects women to all five
> seats, and thus that we need to modify it in a good way in order to
> satisfy the constraints.

Oh, sorry. I didn't see the part about that you could use a proportional 
ranking method. In that case, the answer's simple. Pick the highest 
ranked council extension that doesn't violate the constraints.

E.g. for Schulze's proportional ranking method, say the candidates are 
W1, W2, W3, M1, M2, M3 (for Woman and Man respectively).

First round, you have a matrix with W1, W2, W3, M1, M2, and M3. Say the 
Schulze winner is M1. That's okay, M1 gets first place.

Second round, you have a matrix with {M1, W1}, {M1, W2}, {M1, W3}, {M1, 
M2}, and {M1, M3}. Determine the Schulze social ordering according to 
the Schulze proportional ordering weights (as defined in his paper). 
Remove {M1, M2} and {M1, M3} from the output social ordering since these 
aren't permitted. Say {M1, W1} wins.

Then you just continue like that. In essence, you're picking the best 
continuation of the ordering given what the constraints force you to do.

You could also just null out the defeat strengths in the proportional 
ordering matrix, but that would produce strategy incentives since 
Schulze doesn't satisfy IIA.




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