[EM] Proportional election method needed for the Czech Green party - Council elections

[Peter Zbornik]

Dear Markus Schulze,

You wrote On Sun, May 9, 2010 at 6:59 PM:
"I recommend that you should solve indecisive situations by using the
numbers of the member ID cards of the candidates."
we have member ID cards, and each of them has a number.
I guess we could give the oldest member of the party the place in case of a
tie, i.e. the person with the lowest number on the ID card.
Is this solution in line with what you recommend?

You wrote On Sun, May 9, 2010 at 6:59 PM:
"Yes, the Schulze STV method and the Schulze proportional ranking method can
handle situations with incomplete individual rankings without sacrificing
any of the good properties."
This would be great. Just to avoid any potential misunderstandings: can
Schulze-STV and Schulze proportional ranking handle ballots on the form "M1
Operator M2 Operator ... Operator Mn", where Operator is in {>, =} and
M1,..., Mn are elements in the set of hopefuls?
That would indeed be a great bonus.

Best regards
Peter Zborník


On Sun, May 9, 2010 at 6:59 PM, Markus Schulze <
markus.schulze at alumni.tu-berlin.de> wrote:

> Dear Peter Zbornik,
>
> you wrote (9 May 2010):
>
> > Basically, I have to come up with some method or way
> > to select one of the two rankings you gave for A10,
> > A12, A23, A33, A67. That is a real problem.
>
> I recommend that you should solve indecisive situations
> by using the numbers of the member ID cards of the
> candidates.
>
>
>
> > By the way, out of pure curiosity, could a hybrid
> > ranked ballot, i.e. a ballot on the form A=B>C=D>E,
> > be used in Schulze-STV in theory, without sacrificing
> > any of the good properties of the method?
>
> Yes, the Schulze STV method and the Schulze proportional
> ranking method can handle situations with incomplete
> individual rankings without sacrificing any of the good
> properties.
>
> Markus Schulze
>
>
> ----
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>
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