[EM] "Beatpath GMC" compliance a mistaken standard? JL
juho4880 at yahoo.co.uk
Sun Jan 11 14:36:03 PST 2009
Ok, that relaxed version of mutual majority degraded faster to basic majority than I expected. Need to think more if there is something to conclude from the "B>A" votes.
--- On Mon, 12/1/09, Kevin Venzke <stepjak at yahoo.fr> wrote:
> From: Kevin Venzke <stepjak at yahoo.fr>
> Subject: Re: [EM] "Beatpath GMC" compliance a mistaken standard? JL
> To: election-methods at electorama.com
> Date: Monday, 12 January, 2009, 12:20 AM
> Hi Juho,
> --- En date de : Dim 11.1.09, Juho Laatu
> <juho4880 at yahoo.co.uk> a écrit :
> > If there is a set of voters that form a
> > majority and they all prefer all candidates
> > of set A to all candidates of set B then
> > candidates of set B should not win.
> > This helps A (as requested) by at least
> > eliminating some of the candidates from
> > competing with A.
> > This criterion may also eliminate all
> > candidates. In such situations the rule of
> > course will not apply.
> > I haven't really thought what implications
> > there are. Any comments?
> I would say you're close to inventing again either MDD
> or beatpath
> GMC / CDTT. All you've essentially said is that if A
> has a majority
> over B, B can't win. Because, each candidate could make
> up their own set.
> Having multiple candidates in a set doesn't make any
> Under MDD the candidates of set B cannot be elected unless
> all candidates
> can be placed in a set B. This is inherently not
> Under beatpath GMC / CDTT the candidates of set B cannot be
> unless they have a majority-strength beatpath to all the
> candidates of
> set A. However, lacking this, the candidates of set B can
> also be
> disqualified when the candidates of set A merely have a
> beatpath to the candidates of set B.
> A few years ago I considered a set where it wouldn't be
> enough for set A
> to merely have a beatpath to set B, in order to disqualify
> candidates. But from what I remember, there were
> monotonicity problems.
> I guess there are probably clone problems also.
> Kevin Venzke
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