[EM] Directional Resistance
Jobst Heitzig
heitzig-j at web.de
Thu Mar 22 02:44:33 PDT 2007
Dear Forest,
nice idea, but I'm almost sure it will not be cloneproof. Consider three
options x,y,z. Then the circuit resistance from x to z is
1 / (1/Rxz + 1/(Rxy+Ryz)).
When we add a y-clone y', it seems we get
1 / (1/Rxz + 1/(Rxy+Ryz) + 1/(Rxy'+Ry'z))
which is smaller. Although all other pairwise circuit resistances will
also decrease, it seems that this will not happen in such a coordinated
way that the winner is preserved.
Yours, Jobst
> Has anybody explored this idea?
>
> Make an electrical circuit with a terminal for each candidate.
>
> For each pair of terminals attach a diode that has a different
> resistance in each direction: the resistance in the direction from
> candidate i to candidate j is proportional to the number of ballots
> on which candidate j is ranked above candidate i.
>
> After all of the diodes are attached measure the circuit resistance
> between terminals i and j.
>
> The candidate X against whom the maximal resistance is minimal is the
> winner.
>
> Forest
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