# [EM] "scored condorcet", etc

Paul Kislanko kislanko at airmail.net
Wed Nov 23 20:21:30 PST 2005

```> Rob Brown wrote:
>
> Abd ul-Rahman Lomax <abd <at> lomaxdesign.com> writes:
> > Color (even gray scale) can instantly show the Condorcet
> winner in a
> > pairwise matrix. I'll use gray scale. When the candidate naming the
> > row wins, leave the background color of the cell white. When the
> > column candidate wins, gray it. The winner is the only
> candidate with
> > a white row all the way across. (Color the cell with the same name
> > row and column white also.)
>
> Yes, but all it shows is the winner, and only if that
> candidate is the condorcet
> winner.  What if the winner is not a condorcet winner?  The
> matrix gives no hint
> of how the winner was arrived at, short of "here's all the
> numbers, get out your
> calculator and have fun!"  Nor does it show anything about
> how non-winners did
> in comparison.  The color hints that "number of pairwise wins" is the
> determining factor, but it's not.
>

As I see it, there are two problems here. First, a Condorcet method is a
process that translates a 3-dimensional input (ballots, alternatives, ranks)
into a two-dimensional represemtation of the result of the process. I played
around with a graphic to show how ranked ballots look when turned into a
bar-graph and it looks like http://www.kislanko.com/poll.jpg, which I didn't

> Basically, it just doesn't communicate what a bar graph does.

Well, the second problem is that a bar graph sometimes isn't able to
communicate enough.  The closest I can come to translating ranked ballots
(NOT a pairwise matrix) into a bar graph along the lines of your example
would be something that has a row for each candidate that shows the
percentage of votes for each rank in different colors in the same bar.

```