[EM] simple question (I think)

[Chris Benham]

rob brown wrote:

> Obviously though, if A has 8 pairwise wins, B has 7, and everyone else 
> has less.....A will be the winner no matter what, right?  Regardless 
> of how close A's wins are and how large B's majorities are?

The Condorcet criterion just says that a candidate that pairwise beats 
*all* the other candidates must win.  (Obviously such a candidate is 
also the Copeland winner,
which is why Copeland is a Condorcet method.)
But the Condorcet criterion doesn't say anything about counting and 
comparing numbers of  "pairwise wins."

> What system would you prefer?

I  might save  Paul the bother of replying by reporting that  (I gather) 
he prefers the non-Condorcet method Bucklin.

> I thought all well-known Condorcet methods begin with a pairwise matrix.

And so they do. Begin and end, in the case of  all the respectable  pure 
rankings Condorcet methods.

My own favourite Condorcet method, Definite Majority Choice (DMC)  also 
looks at  approval scores.


Chris  Benham