[EM] Russ´s Better-Than-Expectaton derivation (was "no subject")
MIKE OSSIPOFF
nkklrp at hotmail.com
Fri Mar 4 07:59:39 PST 2005
I´d said:
>So the voter using that strategy votes for a candidate if that candidate is
>so good that s/he would rather have that candidate in office than hold the
>election.
Russ replied:
You never answered my question about what it would mean to not "hold the
election."
I reply:
That´s correct. I didn´t reply because the answer is so obvious.
Russ continues:
Does that mean the incumbent stays in office, or does it mean
that the government ends and anarchy begins?
I reply:
What did I say? :-)
Let me walk you through this, Russ:
>So the voter using that strategy votes for a candidate if that candidate is
>so good that s/he would rather have that candidate in office than hold the
>election.
I didn´t say that the voter would rather have the incumbant in office, or no
one at all in office. What did I say? I said if the voter would rather have
that candidate in office than hold the election. Not the incumbant, not no
one in office, but that candidate in office.
Nor did I say that the voter has the power to put that candidate into office
instead of holding the election. I merely said if that voter would rather
have that candidate in office than hold the election.
>One can come up with situations in which that isn´t optimal. But it
>maximizes one´s utility expectation if certain approximations or
>assumptions are made. One usual assumption is that there are so many voters
>that one´s own ballot won´t change the probabilities significantly. By one
>approach, it´s also necessary to assume that the voters are so numerous
>that ties & near-ties will have only 2 members, and that Weber´s Pij =
>Wi*Wj, the product of the win-probabilities of i & j.
That's called dropping second-order terms, the product of two small
quantities.
I reply:
The assumption that Weber´s Pij = the product of Wi*Wj is called dropping
second-order terms, the product of two small quantities? :-)
And, about the assumption that any ties or near-ties will have only 2
members, that isn´t really called dropping second-order terms, the product
of two small quantities, because we aren´t calculating the probability of a
tie. We´re merely noting that the ties and near-ties with three members are
less likely, and ignoring them. If calculating those less likely
probabilities involves a product of two small numbers, then we´d drop the
terms consisting of those products _if we were calculating the probability
of a tie or near-tie_. But we aren´t.
>But, instead of the last 2 assumptions named in the previous paragraph, it
>would also be enough to assume that when your vote for a candidate
>increases his win-probability, it decreases everyone else´s win-probability
>by a uniform factor.
>
>That´s the approach that Russ used, except that he didn´t state that
>assumption.
You reply:
Yes I did. I said that the other winning probability ratios should
remain unchanged.
I reply:
You didn´t say why. You didn´t say they needed to remain unchanged because
that´s an assumption on which your derivation depends. You said, and I
quote: "...so each individual probability needs to be normalized by dividing
by 1 + delta Pj to keep the sum of all probabilities at unity without
changing the probability ratios." You stated the goal of not changing the
probaility ratios, but you didn´t say anything to indicate that the
assumptoin that all the non-j win-probabilities are reduced by the same
factor is the assumption that makes your derivation possible.
Mike Ossipoff
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