[EM] primary election thoughts
Daniel Bishop
dbishop at neo.tamu.edu
Fri Feb 18 18:33:50 PST 2005
Ted Stern wrote:
>What do group members think of the following primary election proposal:
>
>- Ballots allow a voter to rank 1st, 2nd or 3rd choice candidates.
>
>- Unlike IRV, more than one candidate can be chosen for any rank.
>
>
If you aren't using IRV, then there's not a huge implementation
advantage to restricting the number of ranks. So why have the restriction?
>- Any 1st/2nd/3rd choice vote is considered an "approval" vote.
>
>- Use Condorcet to tally.
>
>- If a Condorcet winner exists, with more than 50% of the voters
> approving, then that candidate wins immediately and the seat doesn't have
> to be decided in the general election.
>
>- Otherwise, eliminate candidates with less than 1% approval.
>
>- On the general election ballot for that seat, candidates will be listed
> with the Condorcet winner (if any) at the top, with remaining candidates
> listed below in order of approval.
>
>This would be an alternative to either Louisiana-style top two runoff or
>closed party primary.
>
>I'm curious what advantages of full Condorcet might be lost by reducing the
>options to only 3 ranks.
>
>
Suppose that the votes are:
499: A>C>B
492: B>C>A
9: C>A>B
Then C, a Condorcet winner with 100% approval, wins immediately.
Suppose that candidates A1, A2, and A3 entered the race, and the voters'
preferences were
499: A>A1>A2>A3>C>B
492: B>C>A>A1>A2>A3
9: C>A>A1>A2>A3>B
If they voted sincerely, their ballots would be:
499: A>A1>A2
492: B>C>A
9: C>A>A1
There is now no longer a Condorcet winner. Candidate A3, with 0%
approval, is eliminated, and the remaining candidates move on the
general election with the ballot order A>A1>C>A2>B.
If the general election uses a Condorcet method, C still has a good
chance of winning. But suppose that now B1, B2, and B3 enter the race,
and the voters' preferences are:
499: A>A1>A2>A3>C>B>B1>B2>B3
492: B>B1>B2>B3>C>A>A1>A2>A3
9: C>A>A1>A2>A3>B>B1>B2>B3
The ballots now become:
499: A>A1>A2
492: B>B1>B2
9: C>A>A1
A is now a Condorcet winner with 50.8% approval, and so wins immediately.
Thus, your proposed method suffers from a perverse failure of
Independence of Clones: It's possible for one candidate (A) to benefit
from clones, while another candidate (B) is hurt by them, in the same
election!
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