[EM] calculating margins in condorcet

[Ernest Prabhakar]

Hi Curt,

On Apr 19, 2004, at 7:19 PM, Curt Siffert wrote:
> Hi, I'm trying to figure out a way to calculate margins for multiple 
> candidates in a Condorcet-counted election, normalized to 100%.

I do it via pairwise ratios for each step.   So, if we have an ordering 
A > B > C > D, where, say:

A/B = 300/200
B/C = 250/100
C/D = 200/20

Then I would normalize that as:
A: 300
B: 200
C: 80
D: 8

I don't know if it is "fair", but it is well-defined, and has the 
useful property that the 'normalizd votes' for the first two candidates 
equal actual votes.

-- Ernie P.

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