[EM] calculating margins in condorcet

[Gervase Lam]

> From: Curt Siffert
> Date: Mon, 19 Apr 2004 19:19:21 -0700
> Subject: [EM] calculating margins in condorcet

> Assume there's a Condorcet Winner for first place.  He beats everyone
> else head-to-head.  Remove him from the ballots, recount, and then
> assume there's another Condorcet Winner for second place, beating
> everyone else head-to-head (except, of course, the first place winner).
>   Etc down the line.  So assume there is very clear ordering of who came
> in first, second, third, etc.
>
> How do you communicate how much everyone is leading everyone else?
> Like, normalized to 100% total.

Would MinMax Condorcet (a.k.a. Plain Condorcet) do?  Just draw up the 
pairwise matrix then order the candidates by each of their worst pairwise 
defeats.

Or may be something based on Copeland (i.e. number of pairwise wins)?

Thanks,
Gervase.