Dear John B. Hodges,
the following example demonstrates that Bucklin
violates consistency.
Situation 1:
4 A > B > C
5 B > C > A
6 C > A > B
Candidate C is the unique Bucklin winner.
Situation 2:
4 A > B > C
5 C > A > B
Candidate C is the unique Bucklin winner.
Situation 1+2:
Candidate A is the unique Bucklin winner.
Markus Schulze