[EM] Query for one and all

[Markus Schulze]

Dear Kevin,

you wrote (2 Sep 2003):
> I think MCA meets Clone Independence and Participation,
> but I'd like to hear reasoning to the contrary.

Situation 1:

   2   A > B > C
   3   B > C > A
   4   C > A > B

   The winner is candidate C.

Situation 2:

   Replacing C by C1, C2, and C3 gives:

   2   A  > B  > C2 > C1 > C3
   3   B  > C3 > C2 > C1 > A
   4   C1 > C2 > C3 > A  > B

   The winner is candidate B.

Markus Schulze