[EM] Query for one and all

[Kevin Venzke]

Markus,

 --- Markus Schulze <markus.schulze at alumni.tu-berlin.de> a écrit : 
> you wrote (2 Sep 2003):
> > I think MCA meets Clone Independence and Participation,
> > but I'd like to hear reasoning to the contrary.

I agree that the below shows a failure of Clone Independence in the method
as it was described by John.

I assume you'd agree that Clone Independence is passed if the number of ranks
is fixed (not based on the number of candidates), and it is permissible to leave 
ranks empty.

Thanks for such a quick response.

Kevin Venzke
stepjak at yahoo.fr


> 
> Situation 1:
> 
>    2   A > B > C
>    3   B > C > A
>    4   C > A > B
> 
>    The winner is candidate C.
> 
> Situation 2:
> 
>    Replacing C by C1, C2, and C3 gives:
> 
>    2   A  > B  > C2 > C1 > C3
>    3   B  > C3 > C2 > C1 > A
>    4   C1 > C2 > C3 > A  > B
> 
>    The winner is candidate B.


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