[EM] Uncountable Ballot

[josh at narins.net]

On Wed, May 07, 2003 at 02:02:19AM -0500, Adam Tarr wrote:
> Josh Narins wrote:
> 
> >> > ex.
> >> >      A   B   C   D
> >> >    / -------------
> >> > A  | x   B   A   D
> >> > B  | B   x   C   B
> >> > C  | A   C   x   C
> >> > D  | D   B   C   x
> >> >
> >
> >On this individual ballot, there is this cycle...
> >A beats C, C beats D, D beats A
> >so it certainly can't be represented as a ranked ballot, so can not be
> >counted with the methods that I have ever heard of.
> 
> I see no reason why these ballots couldn't be summed and evaluated using a 
> standard Condorcet method such as ranked pairs.
> 

Then you didn't understand.

Pretend the election involved only 1 ballot, the above one.

Please "sum" it and determine the winner using Condorcet.  One can not,
because there is no "rank" order on this ballot.