[EM] Uncountable Ballot

[Adam Tarr]

Josh Narins wrote:

> > > ex.
> > >      A   B   C   D
> > >    / -------------
> > > A  | x   B   A   D
> > > B  | B   x   C   B
> > > C  | A   C   x   C
> > > D  | D   B   C   x
> > >
>
>On this individual ballot, there is this cycle...
>A beats C, C beats D, D beats A
>so it certainly can't be represented as a ranked ballot, so can not be
>counted with the methods that I have ever heard of.

I see no reason why these ballots couldn't be summed and evaluated using a 
standard Condorcet method such as ranked pairs.

-Adam