[EM] Another interesting method: Lin's Eigenvector Method

[Markus Schulze]

Dear Paul,

you wrote (5 Aug 2003):
> Markus Schulze wrote (5 Aug 2003):
> > Lin's method violates independence from clones.
> >
> > Example 1:
> >
> > A:B=20:10
> > A:C=10:20
> > B:C=20:10
> >
> > The winner is [1, 1, 1] / 3.
>
> Since A, B, and C are possible winners, please explain what
> you mean by [1, 1, 1]/3 is the winner.

I mean that A's score is 1/3, B's score is 1/3, and C's score
is 1/3. Similarily, in example 2 A's score is 21/112, B's score
is 25/112, C1's score is 22/112, C2's score is 22/112, and C3's
score is 22/112. Sorry for the missing clearness.

Markus Schulze