[EM] Re: Borda-Elimination

[Kevin Venzke]

 --- Rob LeGrand <honky1998 at yahoo.com> a écrit : 
>  If a candidate wins each pairwise matchup, that score will always be
> positive, and the sum of all Borda scores is zero, so a Condorcet winner's
> Borda score is always above average.  Therefore it won't be eliminated at
> any stage of Baldwin or Nanson, so Baldwin and Nanson are Condorcet methods.

Thank you.  That makes me wonder if Borda-Elimination can be rephrased in a 
manner which makes it look more like a Condorcet method.  It impresses me
that there's no need for a cycle-breaker.

Kevin Venzke
stepjak at yahoo.fr


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