[EM] Another interesting method: Lin's Eigenvector Method

[Markus Schulze]

Dear Rob,

Lin's method violates independence from clones.

Example 1:

  A:B=20:10
  A:C=10:20
  B:C=20:10

  The winner is [1, 1, 1] / 3.

Example 2:

  C is substituted by a set of clones C1, C2, C3.

  A :B =20:10
  A :C1=10:20
  A :C2=10:20
  A :C3=10:20
  B :C1=20:10
  B :C2=20:10
  B :C3=20:10
  C1:C2=20:10
  C1:C3=10:20
  C2:C3=20:10

  The winner is [21, 25, 22, 22, 22] / 112.

Markus Schulze