[EM] Teetor Totter Tiebreaker Method

[Richard Moore]

This is almost equivalent to: Elect the CW if there is one, 
if there isn't then elect the Borda winner. Instead of using 
Borda weights of +2, +1, 0, Demo uses +1, 0, -1. So as long 
as nobody truncates, the number of rankings for each 
candidate is constant, and we subtract the same constant 
from each candidate's Borda count to get the candidate's 
Demo count.

Richard


DEMOREP1 at aol.com wrote:
> Kids play on teetor totters -- a beam with a fulcrum in the middle. 
> 
> A kid sits on each end of the beam and goes up and down.  Great fun (if one 
> is a kid).
> 
> Modifying it for elections (less fun, more math) --
> 
> If there is NO Condorcet Winner in the single winner case, then just do 
> simple torque math from physics.
> 
> Odd number of choices-
> 
>      Place Votes
> 
>      1     2     3
> 
> A   A1    A2    A3
> B   B1    B2    B3
> C   C1    C2    C3
> 
> For each choice -- do 1st place minus 3rd place votes.
> 
> The net torque/tilt will be down left (positive) or down right (negative).
> 
> Highest positive wins.
> 
> See below note for 5, 7, etc. math.
> 
> Even number of choices
> 
>         Place Votes
> 
>      1    2     3     4
> 
> A   A1   A2    A3    A4
> B   B1   B2    B3    B4
> C   C1   C2    C3    C4
> D   D1   D2    D3    D4
> 
> The fulcrum (mid point) is 2.5.
> 
> For each choice -- do (1st minus 4th) x 1.5 plus (2nd minus 3rd) x O.5.
> 
> Highest positive wins.
>  
> For 5, 7, etc. odd choices the multipliers would be whole numbers.
> 
> As usual --- since place votes ONLY show *relative* votes, using a YES/NO 
> vote on each choice would show more accurate *absolute* votes.
> 
> 
>