# [EM] Teetor Totter Tiebreaker Method

Richard Moore rmoore4 at home.com
Fri Aug 10 19:38:45 PDT 2001

```This is almost equivalent to: Elect the CW if there is one,
if there isn't then elect the Borda winner. Instead of using
Borda weights of +2, +1, 0, Demo uses +1, 0, -1. So as long
as nobody truncates, the number of rankings for each
candidate is constant, and we subtract the same constant
from each candidate's Borda count to get the candidate's
Demo count.

Richard

DEMOREP1 at aol.com wrote:
> Kids play on teetor totters -- a beam with a fulcrum in the middle.
>
> A kid sits on each end of the beam and goes up and down.  Great fun (if one
> is a kid).
>
> Modifying it for elections (less fun, more math) --
>
> If there is NO Condorcet Winner in the single winner case, then just do
> simple torque math from physics.
>
> Odd number of choices-
>
>
>      1     2     3
>
> A   A1    A2    A3
> B   B1    B2    B3
> C   C1    C2    C3
>
> For each choice -- do 1st place minus 3rd place votes.
>
> The net torque/tilt will be down left (positive) or down right (negative).
>
> Highest positive wins.
>
> See below note for 5, 7, etc. math.
>
> Even number of choices
>
>
>      1    2     3     4
>
> A   A1   A2    A3    A4
> B   B1   B2    B3    B4
> C   C1   C2    C3    C4
> D   D1   D2    D3    D4
>
> The fulcrum (mid point) is 2.5.
>
> For each choice -- do (1st minus 4th) x 1.5 plus (2nd minus 3rd) x O.5.
>
> Highest positive wins.
>
> For 5, 7, etc. odd choices the multipliers would be whole numbers.
>
> As usual --- since place votes ONLY show *relative* votes, using a YES/NO