[EM] Maybe a new thread is in order ...
Craig Carey
research at ijs.co.nz
Thu Oct 28 17:57:35 PDT 1999
At 19:52 28.10.99 , David Catchpole wrote:
>On Thu, 28 Oct 1999, Craig Carey wrote:
...
>couldn't work it out from the plain English, I'll have a go at putting it
>in a formal structure of proof. Later, though...
Proof of what?.
>> FPTP is a monotonic preferential voting method, and it isn't Condorcet.
>> So therefore the and rule is finally rejected.
>
>It's not! Consider the following example I gave to Markus Schultze-
FPTP is monotonic method. There need not be misunderstanding over that.
Mr Catchpole is redefining the word monotonic. I suggest it be called
David-Catchpole-Monotonicity-version-0.1.
>Say two voters have preferences A>C>B in an election where A has 5
>votes (including that of this voter), B has 4 votes and C has 1. A
>wins. Say that these two voters change their preferences to C>A>B. B now
>wins, even though nobody changed their preferences between A and B. While
>some definitions of monotonicity fail to rule on such a scenario, the one
>I gave in my message does- and rules FPTP out. (more further down)
First example: (1)
3 A
2 AC A wins
4 B
1 C
FPTP,STV,IFPP: A wins
The Second example: (2)
3 A
4 B
2 CA B wins
1 C
FPTP,IFPP: B wins
STV : draw between A and B
Mr Catchpole probably wants A to win election (2)
Here's why "Catchpole monoticity" is with importance (28 October 1999).
Assume the method need not be STV.
Assume the STV property which is that a candidate's win-lose state
is unaffected by altering preferences (on any paper or papers) after
the preference for that candidate.
So A wins the first if and only if A wins this: (3)
5 A
4 B
1 C
Therefor A wins the first and Mr Catchpole must have been wanting B to
lose the 2nd election.
Suppose that C won the 2nd; then by applying that invariance of outcome
on truncating rule, C ought would this: (4)
3 A
4 B
3 C
That is not permissable, so C does not win the 2nd. Mr Catchpole objected
to B winning (since it was found that there was no objection to A winning
the first). So Mr Catchpole must (perhaps), want A to win the second
example.
Let it be supposed that A does win the second: (2)
3 A
4 B
2 CA
1 C
Then A will also win this, by applying the rule that the outcome of
a candidate is unaffected by alterations after any preference(s) for
candidate. If A wins this following example then B and C must lose): (6)
0.9 A
2.1 AC
4 B
2 CA
1 C
An asymmetry style argument would have either C win, or B win, and in
both cases, A would lose.
When A loses (6), A must lose (2) too.
Since C loses (4), C must lose (2) too.
Since A and C lose (2), then B wins (2) (by using what could be regarded
as the first axiom of preferential voting theory)
Mr Catchpole's monotonicity disagreed with A winning (1) or B winning (2),
and it must have been the latter since A wins (3) and hence it wins (1).
So Catchpole monotonicity is now a dead idea (or else the saved by the
presence of a tie on considering just first preferences.)
... [An N rule omitted]
______________________ ______________________
Mr G. A. Craig Carey Auckland, New Zealand research at ijs.co.nz
Snooz Metasearch: http://www.ijs.co.nz/info/snooz.htm
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