[EM] "Spokane" method
DEMOREP1 at aol.com
DEMOREP1 at aol.com
Fri Mar 29 23:28:09 PST 1996
Adding last choices
a,b,c,d-e
a,b,c,d-e
a,b,c,d-e
b,a,c,d-e
c,b,a,d-e
c,b,a,d-e
d,c,e,b-a
e,d,c,b-a
e,d,c,b-a
e,d,c,b-a
Head to head winners
Spok Cond
a,b 3, 3 3, 7 *
a,c 4, 2 4, 6 *
a,d 6, 0 6, 4
a,e 0, 0 6, 4 *
b,c 4, 6
b,d 6, 4
b,e 0, 4 6, 4 *
c,d 6, 4
c,e 1, 3 7, 3 *
d,e 1, 3 7, 3 *
*= Condorcet head to head winner changes compared to Spokane
Condorcet summary
a >d,e
b,c> a
b,c>a>d,e
b>d,e
c>d,e
c>b c is Condorcet winner
Comments-- The Spokane example is set up to produce its result using the
Spokane method- 10 total votes using the 10 possible candidate combinations.
Note that only the b,c,d combinations have a total of 10 votes in the Spok
column above with the Condorcet result of them being c>b>d.
The Spokane method is approval voting in rotation for n-1 choices, n-2
choices, n-3 choices, etc. (n= number of candidates) and eliminating the
least approved in each round. (instant run offs) or another words- a form of
approval voting with instant runoffs.
The Spokane method most certainly does not conform with the plain Condorcet
method.
Truncated ballots would cause candidates to be eliminated earlier.
Also, a Condorcet winner as the first choice on 6 ballots would be eliminated
in a Spokane method first round (a direct violation of majority rule) if each
of the other four candidates were mentioned 7 or more times on the 10 ballots
(40 Spokane positions (10 ballots x 4) minus 6 = 34 positions for the other
four candidates or an average of 8.5 positions).
If anything the Spokane method shows a fatal defect in approval voting if the
votes in approval voting are not exactly equal.
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