<div dir="auto">Just as Borda is an attempt to quantify normal rankings, i.e. convert them into ratings, so also we could attempt to convert ranked rankings into ratings. If we did it correctly it would yield a clone free method, unlike Borda.<div dir="auto"><br></div><div dir="auto">It would be a natural generalization of Dyadic Approval, if you remember that from fifteen years ago.</div></div><br><div class="gmail_quote"><div dir="ltr">El jue., 14 de oct. de 2021 1:24 a. m., robert bristow-johnson <<a href="mailto:rbj@audioimagination.com">rbj@audioimagination.com</a>> escribió:<br></div><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><br>
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> On 10/13/2021 9:09 PM Forest Simmons <<a href="mailto:forest.simmons21@gmail.com" target="_blank" rel="noreferrer">forest.simmons21@gmail.com</a>> wrote:<br>
> <br>
> <br>
> Just as rankings allow you to order preferences without specifying a numerical strength of preference, so ranked preferences allow one to order the preference strengths without quantifying those strengths numerically ... for example the notation<br>
> A>B>>>C>>D>>>>E<br>
> <br>
> <br>
> makes clear that the strongest preference shown is D>>>>E and the weakest is A>B, but the notation does not imply that the stronger of these is four times as strong as the weaker.<br>
> <br>
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but it implies that it's stronger than B>>>C which is stronger than C>>D which is stronger than A>B . Sure, maybe we can assign the strength of A>B as -inf, that of C>>D to be zero, B>>>C to be sqrt(pi) and D>>>>E to be +inf, but that wouldn't be particularly meaningful. It **is** some quantitative information. Not just preferential.<br>
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r b-j . _ . _ . _ . _ <a href="mailto:rbj@audioimagination.com" target="_blank" rel="noreferrer">rbj@audioimagination.com</a><br>
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