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<div>Very Good! You are a technical writing genius!</div>
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<div>A selling point ... it works by unification (amalgamation), not mere elimination. Members of the absorbed group (that would have been summarily discarded by a less provident method) may continue to inform the outcome or, in other words, contribute to the
democratic strength of the group.</div>
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<div dir="auto" style="font-size:85%; color:#575757">Sent from my MetroPCS 4G LTE Android Device</div>
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<div>-------- Original message --------</div>
<div>From: Daniel Carrera <dcarrera@gmail.com> </div>
<div>Date: 7/9/21 4:41 PM (GMT-08:00) </div>
<div>To: Susan Simmons <suzerainsimmons@outlook.com> </div>
<div>Cc: election-methods@lists.electorama.com </div>
<div>Subject: Re: [EM] Teams </div>
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<span style="font-family:Arial,Helvetica,sans-serif">On Fri, Jul 9, 2021 at 4:27 PM Susan Simmons <<a href="mailto:suzerainsimmons@outlook.com">suzerainsimmons@outlook.com</a>> wrote:</span><br>
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<div>Did anybody recognize Teams as a reformulation of River?</div>
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<div>It shows that it is not necessary to explicify the implicit tree structure induced by the successive engulfing of one team by another.</div>
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<div>Does this simplified formulation increase River's chances of public adoption?</div>
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It took me some effort to understand the Teams method, but maybe I'm not a good test. I'm only a little smarter than your average koala ;-) But let me offer a different way to write the Teams / River method that might be a little easier to follow. Among other
things, I removed the sports analogy, moved some of the core concepts higher up, and inserted some redundancy. Let me know what you think:</div>
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Overview... the count is based on the pairwise support matrix.</div>
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The winner is elected via a series of rounds in which candidates are merged into groups, where each group has a unique head. The first round begins with every candidate being the sole member of a one-member group. Each round consists of two steps:<br>
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1. Identify two groups to merge. Find the group “A” for which the head of the group has the greatest pairwise loss against any member of another group.<br>
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2. Group “A” is merged into the group of the pairwise winner from step (1) and the previous head of group “A” is no longer the head of any group.<br>
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The rounds end when all candidates have been merged into one group. The head of this one group is elected.
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Cheers,</div>
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Daniel</div>
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