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<p>Robert,<br>
<br>
Another Condorcet-compliant method that might interest you, from a
Kevin Venzke webpage:<br>
<br>
<blockquote type="cite"><b>Jobst Heitzig's River method</b> is
identical to Tideman's method, except that one additionally
ignores (without locking) defeats against candidates against
whom some defeat has already been locked. This is possibly the
easiest of the three to work out by hand.</blockquote>
The other two he is referring to are Schulze and Tideman RP.??
Nearly all the time it will elect the same candidate and as far as
I know is at least as good.<br>
</p>
<p>I strongly suggest that the measure of defeat strength should be
Losing Votes and that ballots that equal-rank A and B above bottom
should contribute a whole vote<br>
to each in the A-B pairwise comparison. Ballots that rank A and B
equal-bottom (or truncate both A and B) should contribute nothing
to the A-B pairwise comparison.<br>
<br>
I'll be posting more on this soonish, but since you asked the
question I thought I'd just give you some food for thought to be
going along with.<br>
<br>
Chris Benham<br>
<br>
</p>
<div class="moz-cite-prefix">On 21/05/2019 6:36 am, robert
bristow-johnson wrote:<br>
</div>
<blockquote type="cite"
cite="mid:47b30f38e2acc5df478f78b385c9cbff.squirrel@webmail04.register.com">
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<p>??</p>
<p>So this would be about Tideman Ranked-Pairs, or Schulze, or
some other Condorcet-compliant method.</p>
<p>It doesn't make much difference if the measure of Defeat
Strength is Margins (supporting votes minus opposing votes), but
what if Winning Votes is the measure of Defeat Strength
in either RP or Schulze??? How should a pair of candidates that
are equally-ranked on a ballot be counted??? Do you count it (as
a winning vote) for *both* candidates??? For neither candidate???
(I dislike the idea of a half-vote for both candidates.?? And I
hate the idea of not
allowing equal-ranking in a Condorcet RCV election.)</p>
<p>What is the right way to do this??? It seems the most consistent
might be to count an equally-ranked votes for **neither**
candidate, since we consider unranked candidates as tied for
last place on the ballot, and we would count those as
votes.</p>
<p>But what do you guys think??? If we allow for equal-ranking in a
Condorcet-compliant RCV, how do we deal with it in terms of vote
totals?</p>
<p><br>
--<br>
<br>
r b-j?? ?? ?? ?? ?? ?? ?? ?? ?? ?? ?? ?? ??<a class="moz-txt-link-abbreviated" href="mailto:rbj@audioimagination.com">rbj@audioimagination.com</a><br>
<br>
"Imagination is more important than knowledge."<br>
??</p>
<p>??</p>
<p>??</p>
<p>??</p>
<br>
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