Juho,<div><br></div><div>we have the example</div><div><span class="Apple-style-span" style="font-family: arial, sans-serif; font-size: 13px; border-collapse: collapse; ">49: A<br>48: B>C<br>3: C>B</span><br><div><br>
</div><div>you wrote to me:</div><div><span class="Apple-style-span" style="font-family: arial, sans-serif; font-size: 13px; border-collapse: collapse; "><div><div>"- C loses to B, 3-48. In winning votes the strength of this loss is 48.</div>
</div><div><div>- B loses to A, 48-49. In winning votes the strength of this loss is 49.</div></div><div><div>- A loses to C, 49-51. In winning votes the strength of this loss is 51."</div></div><div><br></div><div>Thus: "If the three C voters will truncate then they will win instead of B in winning votes based Condorcet methods."</div>
<div><br></div><div>This is correct, if proportional completion is not used (see page 42 in <span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; "><a href="http://m-schulze.webhop.net/schulze2.pdf">http://m-schulze.webhop.net/schulze2.pdf</a>)</span></div>
<div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; ">If proportional completion is used (which I would recommend) then B wins.</span></div><div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; "><br>
</span></div><div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; ">If proportional completion is used, then we need to fill in the preferences of the ones who did not vote:</span></div>
<div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; ">We have 100 voters.</span></div><div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; "><span class="Apple-style-span" style="font-family: arial, sans-serif; font-size: 13px; border-collapse: collapse; ">- C loses to B, 3-48, means 49 voters did not vote. We split each voter into two: the first has weight 3/51 of a vote and the second 48/51, which gives a total score of 49*3/51+3 vs 49*48/51+48</span></span></div>
<div><span class="Apple-style-span" style="border-collapse: separate; font-family: arial; font-size: small; "><span class="Apple-style-span" style="font-family: arial, sans-serif; font-size: 13px; border-collapse: collapse; ">- B loses to A, 48-49, means 3 voters did not vote. We split each voter into two: the first has weight 48/97 and the second 49/97, which gives a total score of </span></span>3*48/97+48 vs 3*49/97+49</div>
<div>- A loses to C, 49-51, means all voters voted.</div><div><br></div><div>Thus after the proportional completion, the vote tally is the following:</div><div>- C loses to B, 5,88-94,12. In winning votes the strength of this loss is 94,12.</div>
<div>- B loses to A, 49,48-50,52. In winning votes the strength of this loss is 50,52. (delete this link first)</div><div>- A loses to C, 49-51. In winning votes the strength of this loss is 51.</div><div><br></div></span><div>
Thus B wins if proportional completion is used. C wins without proportional completion.</div><div><br></div><div>Best regards</div><div>Peter Zborník</div><br><div class="gmail_quote">On Wed, Jun 16, 2010 at 9:35 PM, Juho <span dir="ltr"><<a href="mailto:juho.laatu@gmail.com">juho.laatu@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;"><div class="im">On Jun 16, 2010, at 9:39 PM, Peter Zbornik wrote:<br>
<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
In what situations will bullet voting help my candidate to win (considering the advanced Condorcet systems)?<br>
</blockquote>
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Here's one more example where a reasonably small number of strategic voters can change the result.<br>
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49: A<br>
48: B>C<br>
3: C>B<br>
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If the three C voters will truncate then they will win instead of B in winning votes based Condorcet methods.<br><font color="#888888">
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Juho</font><div><div></div><div class="h5"><br>
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