<div> <font face="Arial, Helvetica, sans-serif">> P: A>C>B<br>
> Q: B>C>A,<br>
<br>
I wonder if it would be worth repeating the draw if no compromise appears.<br>
<br>
The chances of each side winning outright would be<br>
<br>
P-win = P^n/(P^n+Q^n)<br>
Q-win = Q^n/(P^n+Q^n)<br>
</font><font face="Arial, Helvetica, sans-serif"><br>
If both are 50/50, then that is the same as a random lottery.<br>
<br>
This system favours the larger side. If n=4 and P was 0.6 and Q was 0.4, then<br>
A would win in 83% of cases. This would mean that P voters would need to rate<br>
C > 8.3 out of 10 before they will compromise.<br>
<br>
The advantage is that it allows recovery if one of the ballots drawn is from a<br>
small hold out group, so compromise fails.<br>
<br>
Another option is to have a limited/finite number of redraws. Maybe this <br>
has basically the same effect as modifing n as it sets the 'chances of<br>
no compromise needed probability'. Also, in practice, it might be needed<br>
as you could be drawing forever, but that would require no candidate to <br>
be approved by n voters. <br>
<br>
If there was 1 re-draw, then that doubles the odds of an A or B outright win. <br>
This means the compromise must be more popular to ensure a win.<br>
<br>
There are ofc some issues if there is more than 3 candidates and deciding who to<br>
approve. <br>
<br>
A feature of this system is that it reverts to random ballot for the 2 candidate case. <br>
This may result in candidates who would be discouraged from running due to spoiler <br>
effects in plurality being encouraged to run due to 'civic duty'.<br>
</font></div>
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<div id="sig8338" style="clear: both;"><font>Raphfrk<br>
--------------------<br>
Interesting site<br>
"what if anyone could modify the laws"<br>
<br>
www.wikocracy.com</font></div>
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