<HTML><BODY>I wonder if this is <span class="correction" id="">sorta</span> similar to a <span class="correction" id="">Borda</span> count in terms of Clone independence.<br>

<br>

For example, if voters, A,B,C  vote<br>

<br>

A: A>B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span><br>


<div>B:  B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span>>A<br>

C: <span class="correction" id="">C1</span>><span class="correction" id="">C2</span>>A>B<br>

<br>

A>B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span>>A<br>

<br>

(Horizontal = first candidate)<br>

<br>

A>B<br>

0 0 0 1<br>

1 0 0 0 <br>

0 0 0 0<br>

0 0 1 0<br>

<br>

B><span class="correction" id="">C1</span><br>


0 0 0 0<br>

1 0 0 1 <br>


0 1 0 0<br>


0 0 0 0<br>

<br>

<span class="correction" id="">C1</span>><span class="correction" id="">C2</span><br>

0 0 0 0<br>

1 0 0 0 <br>



0 1 0 0<br>



0 0 1 0<br>

<br>

<span class="correction" id="">C2</span>>A<br>


0 0 0 1<br>


0 0 0 0 <br>


0 1 0 0<br>


0 0 1 0<br>


<br>

The lowest ranked box is 4,4 and it is empty.  The next lowest is (3,4) and (4,4)<br>

and only 3,4 has votes in it.<br>

<br>

<span class="correction" id="">C2</span>>A, <span class="correction" id="">C1</span>><span class="correction" id="">C2</span> and A>B have pairs in that box.  The only pair left is B><span class="correction" id="">C1</span>.  <br>

Thus, B wins?<br>

<br>

I am not 100% sure if I have understood you method correctly.  However, by<br>

 weighting lower preferences lower, the C "Party" has reduced the weighting<br>

 of  A>B in ballot C and <span class="correction" id="">C2</span>>A in ballot B.  Without the first one, the votes <br>

become:<br>

<br>

A: A>B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span><br>


B:  B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span>>A<br>


C: <span class="correction" id="">C1</span>><span class="correction" id="">C2</span>>A<br>

<br>

A=B<br>

A<<span class="correction" id="">C1</span><br>

A<<span class="correction" id="">C2</span><br>

<br>

B>C1<br>

B>C2<br>

<br>

C1>C2<br>

<br>

B draws to A and wins to C1 and C2.<br>

<br>

The effect seems to be opposite to <span class="correction" id="">Borda</span>, cloning can result in your least favorite<br>

 winning.  That would likely lead to 2 party domination if cloning hurts a cause.<br>

<br>

Is your method <span class="correction" id="">equavalent</span> (or very similar) to the following method.<br>

<br>

1) Voters rank N candidates<br>

2) M=N<br>

3) Ballots truncated to M rankings<br>

</div>

<div>4) <span class="correction" id="">Condorcet</span> winner is elected, if existing<br>

5) Otherwise, reduce M by 1 and <span class="correction" id="">goto</span> 3)<br>

<br>

What about this instead<br>

<br>

1) Voters rank N candidates and include a range score<br>

2) M=N-1<br>

3) Ballots reduced to at most M clear preferences, least strong preferences <span class="correction" id="">equalised</span> first<br>

4)  <span class="correction" id="">Condorcet</span> winner is elected, if existing<br>


5) Otherwise, reduce M by 1 and <span class="correction" id="">goto</span> 3)<br>

<br>

<br>

<span class="correction" id="">Ok</span>, so I could fill in the following ballot:<br>

<br>

<span class="correction" id="">A1</span>:  1 (99) <br>

<span class="correction" id="">A2</span>:  2 (97)<br>

 B:  3 (90)<br>

 <span class="correction" id="">C1</span>: 4 (0)<br>

 <span class="correction" id="">C2</span>: 5 (1)<br>

<br>

The voter  messed up the ballot for <span class="correction" id="">C1</span> and <span class="correction" id="">C2</span> and also didn't rank <span class="correction" id="">E1</span> or <span class="correction" id="">E2</span>.<br>

<br>

In effect, that preference will be <span class="correction" id="">equalised</span> first due to the contradiction <br>

(shown in bold below).<br>

<br>

So, my ballot would effectively be<br>

Round 1:  <span class="correction" id="">A1</span>><span class="correction" id="">A2</span>>B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span>><span class="correction" id="">E1</span>=<span class="correction" id="">E2</span> (from ballot)<br>

Round 2:  <span class="correction" id="">A1</span>><span class="correction" id="">A2</span>>B><span class="correction" id="">C1</span>><span class="correction" id="">C2</span>><span class="correction" id="">E1</span>=<span class="correction" id="">E2</span>  (already has 1 equality so no change required)<br>

Round 3:  <span class="correction" id="">A1</span>><span class="correction" id="">A2</span>>B><span class="correction" id="">C1</span>=<span class="correction" id="">C2</span>><span class="correction" id="">E1</span>=<span class="correction" id="">E2</span>  (<b>-1 point</b> difference between <span class="correction" id="">C1</span> and <span class="correction" id="">C2</span>)<br>

Round 4:  <span class="correction" id="">A1</span>><span class="correction" id="">A2</span>>B><span class="correction" id="">C1</span>=<span class="correction" id="">C2</span>=<span class="correction" id="">E1</span>=<span class="correction" id="">E2</span>  (1  point difference between  <span class="correction" id="">C2</span> and '0')<br>

Round 5:  <span class="correction" id="">A1</span>=<span class="correction" id="">A2</span>>B><span class="correction" id="">C1</span>=<span class="correction" id="">C2</span>=<span class="correction" id="">E1</span>=<span class="correction" id="">E2</span> (2 point difference between  <span class="correction" id="">A1</span> and <span class="correction" id="">A2</span>) <br>

Round 6:  <span class="correction" id="">A1</span>=<span class="correction" id="">A2</span>=B><span class="correction" id="">C1</span>=<span class="correction" id="">C2</span>=<span class="correction" id="">E1</span>=<span class="correction" id="">E2</span> (10 point difference between <span class="correction" id="">A2</span> and <span class="correction" id="">B2</span>)<br>

Round 7:  <span class="correction" id="">A1</span>=<span class="correction" id="">A2</span>=B=<span class="correction" id="">C1</span>=<span class="correction" id="">C2</span>=<span class="correction" id="">E1</span>=<span class="correction" id="">E2</span> (90 point difference between B and <span class="correction" id="">C1</span>)<br>

<br>

The preferences are converted to equalities in order of increasing difference.<br>

<br>

If round 7 happened, then the election has produced no winner.  Maybe in such a <br>

situation, switch to Range to decide the winner.   <i></i>I am not sure how rare it would <br>

be though.  <br>

<br>

If two preferences have the same difference, then blank out the lower one first maybe.  <br>

Alternatively, blank out both (and thus  none on the next round).  In any case, a rule <br>

needs to be applied.<br>

<br>

This system would be pretty complex though.  Each district could produce a <br>

digest, however, it will require N^3 boxes.  Basically, they need to produce<br>

a standard <span class="correction" id="">condorcet</span> digest for each round and there can be up to N-1 rounds. <br>

Another option is that they produce only rounds 1-10 and only count  more <br>

rounds if necessary.<br>

<br>

It is more clone resistant than always using the lower ranked preferences.  It<br>

allows voters to say who are the clones.  If a voter thinks 2 candidates are<br>

clones, then they will rate them with the same score.  This means they lose<br>

minimum <span class="correction" id="">expressivity</span>.  C1>C2 is almost as good as C1=C2 as they are clones<br>

and the voter will want to drop that preference before they drop their main<br>

preferences.<br>

<br>

<br>

</div>

<div style="clear: both;"><span class="correction" id="">Raphfrk</span><br>
--------------------<br>
Interesting site<br>
"what if anyone could modify the laws"<br>
<br>
<span class="correction" id="">www</span>.<span class="correction" id="">wikocracy</span>.<span class="correction" id="">com</span></div>
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