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<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2><SPAN
class=675534722-14122005>Just a thought for your endeavor. A way to save "more"
information than the pairwise matrix but less than saving counts of each ballot
configuration is to save an NxN matrix with column headings being count of #1,
#2, ... #N ranks and rows being the Alternatives. Use the
rule:</SPAN></FONT></DIV>
<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2><SPAN
class=675534722-14122005></SPAN></FONT> </DIV>
<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2><SPAN
class=675534722-14122005>If equals are found, assign the next alternative rank
(r+1) where where r is the rank the previous alternative listed would've had if
there were no equals. I.e. ranks are assigned 1,1,3 for A=B>C.
</SPAN></FONT></DIV>
<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2><SPAN
class=675534722-14122005></SPAN></FONT> </DIV>
<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2><SPAN
class=675534722-14122005>This takes no more space than the pairwise matrix, but
contains much more information. See <A
href="http://football.kislanko.com/2005/bucklincomps.html">http://football.kislanko.com/2005/bucklincomps.html</A> for
an example with 119 alternatives and any number of voters.</SPAN></FONT></DIV>
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