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Paul Kislanko wrote:
<blockquote cite="midE1ETfdV-0004sG-2k@covert.iadfw.net" type="cite">
<blockquote type="cite">
<pre wrap="">40 A=B>D
35 D>B
25 C>D
Now candidate D wins, with 100 votes in the second round."
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<pre wrap=""><!---->
No. 40 A=B>D is still 40 votes for D no higher than third. So in the second
round D has 60 votes.
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In Bucklin proper, yes, but in the "just go down one slot per
'Bucklin' move" method on those 40 ballots A and B are<br>
both in the top slot and D is in the second slot. The method referred
to doesn't (in a sense) take any notice of how many<br>
candidates are in each slot. <br>
<br>
That method is "in round x each ballot just gives a whole vote to
every candidate it has in slot x, until at the end of a round <br>
one or more candidates has tally of votes greater than half the total
number of valid ballots, at which point elect the candidate <br>
with the highest tally."<br>
<br>
That describes the method that Kevin's example was referring to, and (I
assume) also what Forest was suggesting.<br>
<br>
Chris Benham<br>
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