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Eric<BR>
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AC 498 A>C 498<BR>
BC 497 B>C 497<BR>
CA 3 C>A 3<BR>
CB 2 C>B 2<BR>
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In an election comparing A with B and ignoring C result A 501, B 499<BR>
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In an election comparing A with C and ignoring B result A 498, C 502<BR>
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In an election comparing B with C and ignoring A result B 497, C 503<BR>
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A beats B, C beats A , C beats B. In pairwise comparison C beats all other candidates and therefore is the winner.<BR>
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How is this wrong ? <BR>
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By 498 AC I meant 498 voters ranked A 1st and C 2nd, 497 BC 497 ranked B 1st and C 2nd, 3CA 3 ranked C 1st and A 2nd, 2CB 2 ranked C 1st and B 2nd.<BR>
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I put what I meant into the Condorcet calculator on your site with A as 0, B as 1 and C as 2 and option 2 (C) won under all three methods.<BR>
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Considering what I wrote if this is wrong I'll have no shortage of answers.<BR>
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David<BR>
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Winners: <BR>
Option Did it win? <BR>
0 no <BR>
1 no <BR>
2 YES <BR>
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Option 0 1 2 <BR>
0 0 501 498 <BR>
1 499 0 497 <BR>
2 502 503 0 <BR>
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