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<pre>5 ABCD
4 BDAC
3 CDAB
1 DBCA</pre>
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<pre>...</pre>
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<pre>P.S. The minimum total distance criterion would give the win to A in the
above example. IRV also picks A. Who would win under the rules of Ranked
Pairs?</pre>
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<p><br>Forest --
<p>all preferences are expressed so all criteria give the same result:
<p>A (8) > B (5), A (9) > C (4), D (8) > A(5), B(10) > C (3), B(9) > D
(4), C(8) > D (5).
<br>So B>C locks, then A>C and B>D.
<br>A>B, D>A, C>D cannot all lock.
<br>Only one solution matches 2 out of those 3 locks: A>B>C>D. It should
be locked. A is winner again.
<br>The 5 possibilities:
<br>A>B>C>D checks 2;
<br>A>B>D>C checks 1;
<br>B>D>A>C checks 1;
<br>B>A>D>C checks none;
<br>B>A>C>D checks 1.
<p>Except if anyone knows a better way to resolve ties...
<br>Steph.
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