[EM] Resistant, monotonicity, and UD
Kristofer Munsterhjelm
km_elmet at t-online.de
Tue Feb 27 03:23:10 PST 2024
On 2024-02-21 19:05, Kristofer Munsterhjelm wrote:
> Here's a thought about how to get resistant set compliance and
> unrestricted domain. If it works, then that's a new combination: no
> other method that I know of has all three. And it would show that
> monotonicity is not incompatible with Resistant, despite IRV making it
> seem like they are.
Replying to myself because I think this is busted. The problem is that
the induction step doesn't hold - it's possible for B's disqualification
path to contain A, and then A can't simply prepend his own
disqualification of B and automatically get a longer path than B. Hence
the resistant set compliance proof fails.[1]
I suspect that the monotonicity proof also fails; unless I'm missing
something, it could be possible that raising A could establish A ~(x)~>
E for some subelection x, and so allow B's path to grow from, say,
B ==> ... ==> A
to
B ==> ... ==> A ==> E
without affecting the length of A's path.
I have some ideas for other monotone methods, but I really need to test
them. If they turn out not to work, I have an idea of how I can use
integer programming to find a template for monotone four candidate
elections that pass resistant and monotonicity, and hopefully learn from
or try to generalize from that.
There's just a lot of work between here and there.
-km
[1] A simple patch is to require that for each step of the path, the
current head node is not disqualified by any candidate lower down the
path, on the current path set and all subsets of it. But that doesn't
fix the monotonicity problem.
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