[EM] electing a variable number of seats

[Andy Jennings]

Isn't Jameson right?  In the non-sequential version of RRV, if there are
only two seats to be awarded and C gets niether of them, then the sum of the
C voter's grades of the elected candidates is zero, which will contribute a
huge negative value to the sum of the logs.

But if C is given one of the two seats, even though only one voter out of
100 liked C, then the C voter will have a positive sum and all the A voters
will have a positive sum, so the sum of the logs will be higher.

I guess you can try to pick a large enough epsilon so that a small group of
voters doesn't have veto power.  Has a good formula been given for choosing
the appropriate epsilon?  If you're considering the limit as epsilon goes to
zero, then it seems to be vulnerable to one voter bullet voting.

Andy



On Wed, May 18, 2011 at 12:15 PM, <fsimmons at pcc.edu> wrote:

>
> Jameson Quinn  wrote ...
>
> Wait a minute.... so under non-sequential RRV, there is no "leftover Hare
> quota" of unrepresented voters? If 99 voters vote A100 B99 and one voter
> votes C100, then C will be in the 2-member parliament? That seems broken.
>
> FWS replies:
>
> Your question has the same answer regardless of which version of RRV is
> used
> (sequential or non):
>
> If there are only two seats, A gets the first and B the second.
> If there are only two seats and repetition is allowed, A gets both of them.
> If there are 100 seats with repetitions allowed, then A gets 99 of them and
> C
> gets one of them.
>
> We allow repetition only if A , B, C, etc represent parties (or if the
> elected
> body uses a weighted voting system).
>
> So the primary interpretation of "A gets two seats" would be two seats come
> from
> the party A.
> ----
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