[EM] Condorcet completion with two tiebreakers

[Kristofer Munsterhjelm]

mrouse1 at mrouse.com wrote:
> (As a side note, it would be fun to
> look at the Yee diagrams of such pairs to see which combined pairs came
> closest to Voronoi diagrams.)

You probably know this, but FYI, if your method involves picking the CW 
when one exists, the method's Yee diagrams will always be Voronoi 
diagrams. To investigate which comes closest, you would have to nix the 
Condorcet winner/Smith/Schwartz selection and do something to the effect of:

1. Determine winner by method A.
2. Determine winner by method B.
3. If the winners are equal, that candidate is elected.
4. Otherwise, elect the candidate that beats the other pairwise.

For 4, you could also experiment with "that beats most pairwise", or 
more generally, "that is closest to first according to a ranked version 
of Smith/Schwartz/Landau/etc". That will pick the CW when either of the 
methods do, but if neither does, it won't.