[EM] Why Not Condorcet?
Dave Ketchum
davek at clarityconnect.com
Sun May 16 19:12:46 PDT 2010
On May 16, 2010, at 6:11 PM, Abd ul-Rahman Lomax wrote:
> At 02:16 PM 5/16/2010, Dave Ketchum wrote:
>> On May 16, 2010, at 9:24 AM, Abd ul-Rahman Lomax wrote:
>>> At 06:34 PM 5/15/2010, Dave Ketchum wrote:
>>>>> Some objections to Condorcet could be:
>>>>> 1. It is not expressive enough (compared to ratings)
>>>> Truly less expressive in some ways than ratings.
>>>> This is balanced by not demanding ratings details.
>>>> And more expressive by measuring differences between each pair
>>>> of candidates.
The base topic is Condorcet. It would take a book to respond to all
your extensions such as IRV. Likewise I see no benefit in adding
Borda - Range/score is an adequate source for ratings. I used care in
mentioning ranking to avoid complications such as you add - and
clearly included equal ratings and rankings. Your extensions could be
useful if they contributed value, but not if they just complicate.
>
>>>
>>> "Demanding" is an odd word to use for "allowing." "Condorcet"
>>> doesn't really refer to ballot form, though it is often assumed to
>>> use a full-ranking ballot. In any case, a ballot that allows full
>>> ranking, if it allows equal ranking and this causes an empty space
>>> to open up for each equal ranking, is a ratings ballot, in fact.
>>> It's Borda count converted to Range by having fixed ranks that
>>> assume equal preference strength. Then the voter assigns the
>>> candidates to the ranks. It is simply set-wise ranking, but the
>>> voter may simply rank any way the voter pleases, and full ranking is
>>> a reasonable option, just as is bullet voting or intermediate
>>> options, as fits the opinion of the voter.
>>
>> Assuming I LIKE A, B & C are almost as good, and I DISlike D:
>>
>> I can rate A=99, B=98, C=98, D=0 or rank A high, B&C each medium, and
>> D low (A>B=C>D).
>
> Dave, you are assuming that the ratings ballot has more ratings than
> candidates. That is precisely what I did not suggest. That's why I
> mentioned "Borda." It seems you are thinking of Range 99 as "Range,"
> when Range is a family of methods, with the range of ratings being,
> normally, from 1-N for Range N. With 4 candidates, the equivalent
> Borda ballot has four ranks (1st, 2nd, and "no vote" perhaps). If
> the ballot allows equal ranking, then, you really have a Range 3
> ballot. So your "simple ranking" would be A>B>C>D or A>C>B>D. With
> no equal ranking allowed, you must choose one of these, but the
> condition of the problem is that you have no basis for this. Is that
> hard, or what?
Since the topic is Condorcet equal ranking can be allowed, and I
clearly indicate use of that.
After describing B and C as equally ranked I used common symbology -
(A>B=C>D) - and am not used to the symbology you use below.
>
> Now allow equal ranking on the same ballot. Yes, you have a choice,
> with the simplest ballot rules: You can rank them A>B=C>.>D (D
> perhaps not being on the ballot, but I'll show the bottom rank), or
> as A>.>B=C>D. It's a trade-off, and which one you pick depends on
> two factors: how strongly do you want to prefer A, and how strongly
> do you want to act against D? Strongly preferring A indicates you
> put both middle candidates in third rank, strongly acting against C
> indicates you might put both middle candidates in second rank. In
> addition, there are the probabilities to consider, which may
> outweigh the preference strength issue. Is it possible for A to win?
> If so, indication is that you should rate B and C lower. Is it
> possible for D to win? If so, then you might want to rate B and C
> higher.
In ranking all I can say is to rank B&C above D and below A..
Go back to the example and see B and C each rated 98 because I DO NOT
want them to lose to D.
>
> If the frontrunners are A and D, *it matters very little where you
> rank B and C*
True, but ranking them below A and above D gave what insurance was
possible.
>
> If you have trouble deciding to go for low ranking or high ranking,
> there is an option that might be allowed in Bucklin or Range: half-
> ranking. The way that A low-res Range 3 ballot might be shown would
> be a list of candidates, with three options for each candidate. If
> you mark more than one option, your vote would be, with range, half-
> assigned to one rank and half to the other. (or a third, etc., if
> you mark more than two, but with this particular ballot you could
> just neglect the middle rank vote, it would end up the same). With
> Bucklin analysis, same, except that in the counting rounds, a
> "middle rank" would be counted after the higher rank and before the
> lower.
Huh?
>
>
> (There are other reasons for defining what such "overvotes" mean,
> basically to avoid discarding ballots that have an apparent meaning.)
>
> It is, in general, easier to rank candidates if the equal ranking
> option exists. The issue, then, is how such equal ranking is to be
> interpreted. IRV rules typically toss the vote. Not allowed. But, in
> some small level of progress, in the U.S., the ballot simply is
> considered exhausted at that point, the higher ranked candidate
> still have their votes (which, if the lower ranked votes, where the
> overvoting was, are being counted, the higher ranked candidates have
> been eliminated. But at least the whole ballot hasn't been tossed.)
Why say this?
>
>> The example ratings of A, B,&C do the most I can to make any of them
>> win over D; the example rankings do the most I can to make A win, D
>> lose, and give B&C an equal chance.
>>
>> In Condorcet I ranked A over B and C over D but could not express the
>> magnitude of these differences. In Score I must rate with numeric
>> values that include the differences.
>
...
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