[EM] Proportional election method needed for the Czech Green party - Council elections
Peter Zbornik
pzbornik at gmail.com
Thu May 6 12:13:23 PDT 2010
Dear Markus Schulze, dear readers,
The example below is intriguing. But I am afraid I fail to understand
this formulation of Schulze's proportional ranking.
I would be grateful if M. Schulze or someone else, could give an
example, which could help me get it.
Specifically, I didn't understand what H[A(1),...,A(n-1),x,y] is. Is
it a function, H[A(1),...,A(n-1),x,y]=min(cardinality of T(i),
0<=i<=n+1 plus other criteria)?, I didn't get the properties of
T(n+1). Why are there n+1 partitions of the electorate and not only n?
Are hopefuls x. y two members of the set of all hopefuls? I guess yes.
Some reference to the definitions in the paper could be useful.
Thank you for you kind help.
Best regards
Peter Zbornik
2010/5/6, Markus Schulze <markus.schulze at alumni.tu-berlin.de>:
> Dear Peter Zbornik,
>
> in the scientific literature, candidates, who
> have not yet been elected, are sometimes called
> "hopeful".
>
> ***************************
>
> The Schulze proportional ranking method can be
> described as follows:
>
> Suppose place 1 to (n-1) have already been
> filled. Suppose A(i) (with i = 1,...,(n-1))
> is the candidate of place i.
>
> Suppose we want to fill the n-th place.
>
> Suppose x,y are two hopeful candidates. Then
> H[A(1),...,A(n-1),x,y] is the largest possible
> value such that the electorate can be divided
> into n+1 disjoint parts T(1),...,T(n+1) such that
>
> 1. For all i := 1,...,n: |T(i)| >= H[A(1),...,A(n-1),x,y].
> 2. For all i := 1,...,(n-1): Every voter in T(i)
> prefers candidate A(i) to candidate y.
> 3. Every voter in T(n) prefers candidate x
> to candidate y.
>
> Apply the Schulze single-winner election method
> to the matrix d[x,y] := H[A(1),...,A(n-1),x,y].
> The winner gets the n-th place.
>
> ***************************
>
> The best way to understand the Schulze proportional
> ranking method is to investigate the properties of
> H[A(1),...,A(n-1),x,y]. For example:
>
> a. Suppose x and y are the only hopeful candidates.
> Suppose N is the number of voters.
>
> Suppose Droop proportionality for n seats requires
> that x must be elected and that y must not be
> elected, then we get H[A(1),...,A(n-1),x,y] > N/(n+1)
> and H[A(1),...,A(n-1),y,x] < N/(n+1), and, therefore,
> H[A(1),...,A(n-1),x,y] > H[A(1),...,A(n-1),y,x].
>
> This guarantees that the Schulze proportional
> ranking method satisfies the proportionality
> criterion for the top-down approach to create
> party lists.
>
> b. Adding or removing another hopeful candidate z
> does not change H[A(1),...,A(n-1),x,y].
>
> c. H[A(1),...,A(n-1),x,y] is monotonic. That means:
>
> Ranking candidate x higher cannot decrease
> H[A(1),...,A(n-1),x,y]. Ranking candidate x
> lower cannot increase H[A(1),...,A(n-1),x,y].
>
> Ranking candidate y higher cannot increase
> H[A(1),...,A(n-1),x,y]. Ranking candidate y
> lower cannot decrease H[A(1),...,A(n-1),x,y].
>
> d. H[A(1),...,A(n-1),x,y] depends only on which
> candidates of {A(1),...,A(n-1),x} the individual
> voter prefers to candidate y, but it does not
> depend on the order in which this voter prefers
> these candidates to candidate y.
>
> This guarantees that my method is not needlessly
> vulnerable to Hylland free riding. In my paper
> (http://m-schulze.webhop.net/schulze2.pdf), I argue
> that other STV methods are needlessly vulnerable to
> Hylland free riding, because the result depends on
> the order in which the individual voter prefers
> strong winners. In my paper, I argue that voters,
> who understand STV well, know that it is a useful
> strategy to give candidates, who are certain of
> election, an insincerely low ranking. I argue
> that, therefore, the order in which the individual
> voter prefers strong winners doesn't contain any
> information about the opinion of this voter, but
> only information about how clever this voter is in
> identifying strong winners. Therefore, the result
> should not depend on the order in which the
> individual voter prefers strong winners.
>
> Markus Schulze
>
>
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