[EM] Sincere Condorcet Cycles

[fsimmons at pcc.edu]

> Here's a natural scenario that yields an exact Condorcet Tie:
> 
> A together with 39 supporters at the point (0,2)
> B together with 19 supporters at (0,0)
> C together with 19 supporters at (1,0)
> D together with 19 supporters at (4,2)
> 
> D is a Condorcet loser.


Think of four cities represented by A, B, C, and D respectively,  with the pairwise distances in miles 
calculated from the above planar coordinates:

        A          B             C               D            

D      4          20^(1/2)     14^(1/2)
C      5^(1/2)     1               
B       2