[EM] Webster clarification

[Michael Ossipoff]

Webster explicitly directly puts each state’s s/q as close to 1 as possible, 
and therefore as close to each other as possible. No pair of states could be 
any closer in s/q.

But, as I recently found out, Webster, when the frequency distribution is 
uniform, also puts each cycle’s expected overall s/q as closed to 1 as 
possible. That (given the uniform distribution) would give to everyone in 
the U.S. the same representation expectation, if it isn’t known what part of 
their cycle the states are in. Or, to put it differently, if we’re looking 
at it with regard to cycles, and not position within cycles.

But if we look at it with regard to position within cycles, there can, with 
any method, be no such thing as unbias or equal expectation.

So Webster, WW, CW & AR, achieve unbias and equal representation expectation 
to the extent that it’s achievable, and in the way that it’s achievable.

Mike Ossipoff