[Election-Methods] RE : Corrected "strategy inCondorcet" section
Dave Ketchum
davek at clarityconnect.com
Fri Aug 17 09:41:27 PDT 2007
Paul's words are tempting, for this exchange has little to do with
desirability of Condorcet, or of margins vs WV.
Looking closer, the votes are:
1000 A>B>C=D
1000 C>D>A=B
1 D>B>A=C
2000 voters rate A vs C as a tie, only agreed that B and D should lose.
The one vote agrees to the A vs C tie, but mostly muddies the water.
So, a not believable election tally gets debated for weeks. True that
margins vs WV is an important topic, but each can offer believable
examples in their favor - serious thought would be based on more
believable examples than debated here.
DWK
On Tue, 14 Aug 2007 17:25:57 -0500 Paul Kislanko wrote:
> This is enough to convince me that approval is an appropriate method.
>
> ------------------------------------------------------------------------
> From: election-methods-bounces at lists.electorama.com
> [mailto:election-methods-bounces at lists.electorama.com] On Behalf Of
> Chris Benham
> Sent: Tuesday, August 14, 2007 5:11 PM
> To: Juho
> Cc: Forest W Simmons; Election Methods Mailing List
> Subject: Re: [Election-Methods] RE : Corrected "strategy inCondorcet"
> section
>
>
>
> Juho wrote:
>
>>On Aug 2, 2007, at 6:44 , Kevin Venzke wrote:
>>
>>
>>
>>>>1000 A>B, 1000 C>D, 1 D>B
>>>>
>>>
>>
>>
>>
>>>Yes, I do think D is the proper winner.
>>
>>Do you have a verbal (natural language) explanation why D is better
>>than A and C. This scenario could be an election in a school. One
>>class has voted A>B (A and B are pupils of that class), another class
>>has voted C>D, the teacher has voted D>B. What should the teacher
>>tell the C>D voting class when they ask "didn't you count our votes"?
>>Maybe this is clear to you. Unfortunately not as clear to me. The
>>teacher vote seemed to be heavier than the pupils votes :-).
>>
>
>
> I agree with Kevin that D is the proper winner, but Winning Votes isn't
> my favourite algorithm.
> If we are sticking with Condorcet "immune" methods and so are only
> focussing on how to compare
> (measure) defeat strengths, then I like Approval Margins (Ranking) if we
> are using plain ranking ballots.
>
> So interpreting ranking (above bottom or equal-bottom) as approval, we
> get these approval scores:
> D1001, B1001, A1000, C1000
>
> All the candidates have at least one pairwise defeat, and by AM the
> weakest is D's single defeat, C>D
> by an AM of -1.
> I also like Approval-Sorted Margins(Ranking), which is probably
> equivalent to AM.
>
> The initial approval order is D=B>A=C. The smallest approval gaps
> (zero) are between D and B, and A
> and C. A pairwise ties with C but D pairwise beats B, so our first
> modification of the order is D>B>A=C.
> A pairwise beats B, so the second modification is D>A>B=C. B pairwise
> beats C, so the third modified
> order is D>A>B>C. This order accords with the pairwise comparisons so
> is the final order and D wins.
>
> I also like eliminating (and dropping from the ballots) the candidate
> lowest in this order and then repeating
> the whole process until one remains. In this case that would give the
> same winner, with the elimination order
> just being the reverse of the ASM(R) order.
>
> The only candidate with any sort of claim versus D is C, and C is
> pairwise beaten by a more approved
> candidate (B) so C is outside the "Definite Majority (Ranking)" set.
>
> Chris Benham
--
davek at clarityconnect.com people.clarityconnect.com/webpages3/davek
Dave Ketchum 108 Halstead Ave, Owego, NY 13827-1708 607-687-5026
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